gdtcontext.WithDebug() no args to stdout

Changes the way that the `gdtcontext.WithDebug()` method works when
passed no arguments. When called with no arguments, we now output
debugging messages to stdout instead of doing the thing with an
io.Discard that was used to call t.Logf().

Signed-off-by: Jay Pipes <[email protected]>

context/context.go

@@ -7,6 +7,7 @@ package context
 import (
 	"context"
 	"io"
+	"os"
 
 	gdttypes "github.com/gdt-dev/gdt/types"
 	"github.com/samber/lo"
@@ -100,18 +101,15 @@ func WithFixtures(fixtures map[string]gdttypes.Fixture) ContextModifier {
 // SetDebug sets gdt's debug logging to the supplied `io.Writer`.
 //
 // The `writers` parameters is optional. If no `io.Writer` objects are
-// supplied, gdt will output debug messages using the `testing.T.Log[f]()`
-// function. This means that you will only get these debug messages if you call
-// the `go test` tool with the `-v` option (either as `go test -v` or with `go
-// test -v=test2json`.
+// supplied, gdt will output debug messages to stdout.
 func SetDebug(
 	ctx context.Context,
 	writers ...io.Writer,
 ) context.Context {
 	if len(writers) == 0 {
-		// This simply triggers a call to t.Logf() when WithDebug() is
-		// called with no parameters...
-		writers = []io.Writer{io.Discard}
+		// This triggers writes to stdout when WithDebug() is called with no
+		// parameters...
+		writers = []io.Writer{os.Stdout}
 	}
 	return context.WithValue(ctx, debugKey, writers)
 }