fix overly-aggressive pruning of types based on features #1958
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Previously, `ast::Resolve` would sometimes assign a `Stability` to types according to the first function it found that type in as a parameter or result. That's a problem if such a function is marked `@unstable`, since it will effectively poison that type and prevent it from being used by any other function -- even if the type itself is ungated. This fixes the problem by removing the `&Stability` parameter from `resolve_params` and `resolve_results` and instead passing `&Stability::Unknown` to `resolve_type` from those functions. Additionally, I've added a new `find_stability` function which recursively inspects a `&TypeDefKind`, looking for a non-unknown stability. If it finds one, it will use that; otherwise, it will default to `Stability::Unknown`. For example, if `option<T>` appears as a parameter type in a function, we'll start by assuming that type has unknown stability, then look to see if `T` has a stability (directly or transitively) and use that if so. Things get interesting in the case of e.g. `tuple<T, U, V>`, where `T`, `U`, and `V` each have their own stability. Currently we just use the first known stability we find, but perhaps there's a better approach to consider? Signed-off-by: Joel Dice <[email protected]>
pchickey
approved these changes
Dec 18, 2024
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Previously,
ast::Resolvewould sometimes assign aStabilityto types according to the first function it found that type in as a parameter or result. That's a problem if such a function is marked@unstable, since it will effectively poison that type and prevent it from being used by any other function -- even if the type itself is ungated.This fixes the problem by removing the
&Stabilityparameter fromresolve_paramsandresolve_resultsand instead passing&Stability::Unknowntoresolve_typefrom those functions. Additionally, I've added a newfind_stabilityfunction which recursively inspects a&TypeDefKind, looking for a non-unknown stability. If it finds one, it will use that; otherwise, it will default toStability::Unknown.For example, if
option<T>appears as a parameter type in a function, we'll start by assuming that type has unknown stability, then look to see ifThas a stability (directly or transitively) and use that if so. Things get interesting in the case of e.g.tuple<T, U, V>, whereT,U, andVeach have their own stability. Currently we just use the first known stability we find, but perhaps there's a better approach to consider?