Automated Commit 🤖

README.md

@@ -35,4 +35,11 @@ LeetCode/
 | 2239 | [Find Closest Number to Zero](https://leetcode.com/problems/find-closest-number-to-zero/description/) | [Python](src/2239-find-closest-number-to-zero.md) |
 | 1342 | [Number of Steps to Reduce a Number to Zero](https://leetcode.com/problems/number-of-steps-to-reduce-a-number-to-zero/description/) | [Python](src/1342-number-of-steps-to-reduce-a-number-to-zero.md) |
 | 169 | [Majority Element](https://leetcode.com/problems/majority-element/description/) | [Python](src/169-majority-element.md) |
-| 231 | [Power of Two](https://leetcode.com/problems/power-of-two/description/) | [Python](src/231-power-of-two.md) |
+| 231 | [Power of Two](https://leetcode.com/problems/power-of-two/description/) | [Python](src/231-power-of-two.md) |
+
+
+## Medium
+
+| ID |              Title                 | Solution |
+|----|------------------------------------|----------|
+| 633 | [Sum of Square Numbers](https://leetcode.com/problems/sum-of-square-numbers/description/) | [Python](src/633-sum-of-square-numbers.md) |

index.html

@@ -76,6 +76,12 @@ <h2>Easy</h2>
 | 169 | <a href="https://leetcode.com/problems/majority-element/description/">Majority Element</a> | <a href="src/169-majority-element.md">Python</a> |
 | 231 | <a href="https://leetcode.com/problems/power-of-two/description/">Power of Two</a> | <a href="src/231-power-of-two.md">Python</a> |</p>
 
+<h2>Medium</h2>
+
+<p>| ID |              Title                 | Solution |
+|----|------------------------------------|----------|
+| 633 | <a href="https://leetcode.com/problems/sum-of-square-numbers/description/">Sum of Square Numbers</a> | <a href="src/633-sum-of-square-numbers.md">Python</a> |</p>
+
     </body>
     </html>
 

src/633-sum-of-square-numbers.md

@@ -0,0 +1,49 @@
+# Sum of Square Numbers
+**URL**: [https://leetcode.com/problems/sum-of-square-numbers/description/](https://leetcode.com/problems/sum-of-square-numbers/description/)
+
+**Description:**
+
+Given a non-negative integer c, decide whether there're two integers a and b
+such that a^2 + b^2 = c.
+
+ __Example 1:__
+```
+Input: c = 5
+Output: true
+Explanation: 1 * 1 + 2 * 2 = 5
+```
+
+ __Example 2:__
+```
+Input: c = 3
+Output: false
+```
+
+ __Constraints:__
+```
+0 <= c <= 2^31 - 1
+```
+
+**Solution Code**:
+```python
+from math import sqrt
+
+class Solution:
+    def judgeSquareSum(self, c: int) -> bool:
+        a = 0
+        b = int(sqrt(c))
+
+        if c <= 2:
+            return True
+
+        while (a<=b):
+            result = (a*a) + (b*b)
+            if result == c:
+                return True
+            if result < c:
+                a += 1
+            else:
+                b -= 1
+        return False
+
+```