python: wrong activate command on fish

[dominik-muc]

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• Completed

Describe the bug / provide steps to reproduce it

1. Open a python project
2. In your shell is automatically ran command source <project_path>/.venv/bin/activate
3. This isn't working as intended. The proper command would be source <project_path>/.venv/bin/activate.fish

Zed Version and System Specs

Zed: v0.167.1 (Zed)
OS: Linux Wayland arch unknown
Memory: 15.5 GiB
Architecture: x86_64
GPU: AMD Radeon RX 6700 (RADV NAVI22) || radv || Mesa 24.3.2-arch1.1

If applicable, add screenshots or screencasts of the incorrect state / behavior

No response

If applicable, attach your Zed.log file to this issue.

Zed.log

[osiewicz]

Do you have activate_script set to fish in your settings?
https://zed.dev/docs/configuring-zed#terminal-detect_venv

[dominik-muc]

Adding this worked. Thank you very much and sorry for my overlook.

However wouldn't it be a nice addition for zed to read SHELL variable and set it automatically?

"activate_script": "auto"
And set it as default setting?

[choucavalier]

agreed! i think Zed should be smart about it and use the right activation script based on the auto-detected shell