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Single plane computation #1144

Answered by pcarruscag
Nicola-Fonzi asked this question in Q&A
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It could be that the tolerance for checking the flatness of a boundary is too tight.
In any case the actual implementation of the boundary is the same.
The deformation and FE solvers will only complain if the symmetry is not axis-aligned.

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Nicola-Fonzi
Dec 28, 2020
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Nicola-Fonzi
Jan 20, 2021
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