Double output with coloredlogs and logging

[jjanis]

Your code causes double output when used in project where I define my own loggers with logging.DEBUG level.

#!/usr/bin/env python3

import logging
import coloredlogs
from datetime import timedelta
from timeloop import Timeloop

logging.basicConfig(level=logging.DEBUG)
coloredlogs.install(level=logging.DEBUG)
logger = logging.getLogger(__name__)

looper = Timeloop()

@looper.job(interval=timedelta(seconds=5))
def work():
    pass

looper.start(block=True)

[sankalpjonn]

Hello Jānis, Thanks for bringing this to my attention, I will fix it when i find some time. In case you have already found a fix for this, i would highly appreciate it if you can create a pull request for it. Thanks again. Regards, Sankalp

…

On Tue, Apr 16, 2019, 15:38 Jānis Judvaitis ***@***.***> wrote: Your code causes double output when used in project where I define my own loggers with logging.DEBUG level. #!/usr/bin/env python3 import logging import coloredlogs from datetime import timedelta from timeloop import Timeloop logging.basicConfig(level=logging.DEBUG) coloredlogs.install(level=logging.DEBUG) logger = logging.getLogger(__name__) looper = Timeloop() @looper.job(interval=timedelta(seconds=5)) def work(): pass looper.start(block=True) — You are receiving this because you are subscribed to this thread. Reply to this email directly, view it on GitHub <#5>, or mute the thread <https://github.com/notifications/unsubscribe-auth/AQDeazB_9VUFRozSnnu4hij9mer5ELB9ks5vhaEZgaJpZM4cx2x_> .

[lockieRichter]

Having this same issue, has this been resolved?

[KoenDierckx]

I solved it this way

# Timeloop has a default logging handler, remove it, so we only use our own handlers (avoids duplicate logs) logging.getLogger('timeloop').handlers.clear()