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poj2251.cpp
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/*
* 现存在一个XYZ不超过30的立体迷宫,S为入口,E为出口,.为路,#不可通过
* 求最短的步数走到出口
* 没做出来 TODO
* */
#include<iostream>
#include<cstdio>
#include<cstring>
#include<queue>
#include<algorithm>
using namespace std;
char map[35][35][35];
int vis[35][35][35];
int k, n, m, sx, sy, sz, ex, ey, ez;
int dx[6] = {-1, 1, 0, 0, 0, 0};
int dy[6] = {0, 0, -1, 1, 0, 0};
int dz[6] = {0, 0, 0, 0, 1, -1};
struct node {
int x, y, z, step;
};
int check(int x, int y, int z) {
if (x < 0 || y < 0 || z < 0 || x >= k || y >= n || z >= m || map[x][y][z] == '#' ||
vis[x][y][z]) {
return 1;
}
return 0;
}
int bfs() {
node a, next;
queue<node> Q;
a.x = sx;
a.y = sy;
a.z = sz;
a.step = 0;
vis[sx][sy][sz] = 1;
Q.push(a);
while (!Q.empty()) {
a = Q.front();
Q.pop();
if (a.x == ex && a.y == ey && a.z == ez) {
return a.step;
}
for (int i = 0; i < 6; ++i) {
next = a;
next.x = a.x + dx[i];
next.y = a.y + dy[i];
next.z = a.z + dz[i];
if (check(next.x, next.y, next.z)) {
continue;
}
vis[next.x][next.y][next.z] = 1;
next.step = a.step + 1;
Q.push(next);
}
}
return 0;
}
int main() {
while (scanf("%d%d%d", &k, &n, &m), n + m + k) {
for (int i = 0; i < k; ++i) {
for (int j = 0; j < n; ++j) {
scanf("%s", map[i][j]);
for (int r = 0; r < m; ++r) {
if (map[i][j][r] == 'S') {
sx = i;
sy = j;
sz = r;
} else if (map[i][j][r] == 'E') {
ex = i;
ey = j;
ez = r;
}
}
}
}
memset(vis, 0, sizeof(vis));
int ans;
ans = bfs();
if (ans) {
printf("Escaped in %d minute(s).\n", ans);
} else {
printf("Trapped!\n");
}
}
return 0;
}