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This idea is fairly complicated, but here's how it works:
By default if you type too many additional keywords, than it won't find matches.
Basically:
X is the minimum number of matches
Y is the number of matches found
Z is how many matches need to be showed, in order to have that minimum number of matches (X - Y)
If Y is less than X:
Find second-best matches
Show Z extra matches
Maybe there should be a divider, or a button somewhere... I do hope we can implement this in a minimalist way to keep the JS organized though. (Just because of the implementation complexity of this idea, can you vote 👍 if you think it's good? Thanks!)
The text was updated successfully, but these errors were encountered:
KTibow
changed the title
[Feature Request] Loose sort if less than X items
[Feature Request] Looser sort if less than X items
Jun 30, 2020
This idea is fairly complicated, but here's how it works:
By default if you type too many additional keywords, than it won't find matches.
Basically:
X
is the minimum number of matchesY
is the number of matches foundZ
is how many matches need to be showed, in order to have that minimum number of matches (X - Y
)Y
is less thanX
:Z
extra matchesMaybe there should be a divider, or a button somewhere... I do hope we can implement this in a minimalist way to keep the JS organized though. (Just because of the implementation complexity of this idea, can you vote 👍 if you think it's good? Thanks!)
The text was updated successfully, but these errors were encountered: