Possible simplification of CapsuleFrag.verify()
#46
Labels
cryptography
Needs attention of someone who knows what they're doing
CapsuleFrag.verify()
#46
At the moment, we check three equations:
h
here is a hash containing all the other values used (exceptu
which is a constant). So it would seem that the equalities are either all true, or all false, and we can only check one of them. This is especially impactful for running verification as a part of an Ethereum contract.Can it be proven?
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