Create an array of a type generated by a custom type builder

[Charly-xepelin]

This is probably more a question than a request.

I have a type called Rut.

I created a generator for it so you can do:

const personFixture = defineFixture<Person>((t) => {
    // other fields
    t.identifier.asRut();
}

How can I do if I need an array of Ruts?

Something similar to:

const personFixture = defineFixture<Person>((t) => {
    // other fields
    t.identifiers.arrayOfFixture((x) => x.asRut(), 5);
}

[jcteague]

Yeah, this is definitely a weak spot. With the current implementation you have two choices:

1. use the as operator, which is basically the built-in escape hatch and let's you do what ever you want.
2. create another extenstion asArrayofRut() which is going to cleanest approach if you have a lot of these. You could use it to encapsulate the as operator.

Here is the test describing it's use.

I think in your case it probably look something like:

const fixture = defineFixture<{ field: Rut[] }>((t) => 
t.field.as((inc) => [t.asRut(), t.Rut()]));

putting it in an extension would let you customize it a bit.