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ReverseWordsInString.java
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//LeetCode_151
//2021.04.15
//Medium
import java.util.ArrayList;
import java.util.List;
// my solution
public class ReverseWordsInString {
public static void main(String[] args) {
System.out.println(new ReverseWordsInString().reverseWords("a good example"));
}
public String reverseWords(String s) {
char[] word = s.toCharArray();
List<Character> list = new ArrayList<>();
char pre = ' ';
for (int i = 0; i < word.length; i++) {
if (i == 0) {
list.add(word[i]);
pre = list.get(i);
continue;
}
if (pre == ' ' && word[i] == ' ')
continue;
list.add(word[i]);
pre = list.get(list.size()-1);
}
String strWord = "";
for (int i = 0; i < list.size(); i++)
strWord += list.get(i);
String[] str = strWord.split(" ");
for(int i = 0; i<str.length/2; i++){
String temp;
temp = str[i];
str[i] = str[str.length-i-1];
str[str.length-1-i] = temp;
}
String answer = String.join(" ", str).trim();
return answer;
}
}
/* USE_투포인터_출처:Leetcode
public class Solution {
public String reverseWords(String s) {
if (s == null) return null;
char[] a = s.toCharArray();
int n = a.length;
// step 1. reverse the whole string
reverse(a, 0, n - 1);
// step 2. reverse each word
reverseWords(a, n);
// step 3. clean up spaces
return cleanSpaces(a, n);
}
void reverseWords(char[] a, int n) {
int i = 0, j = 0;
while (i < n) {
while (i < j || i < n && a[i] == ' ') i++; // skip spaces
while (j < i || j < n && a[j] != ' ') j++; // skip non spaces
reverse(a, i, j - 1); // reverse the word
}
}
// trim leading, trailing and multiple spaces
String cleanSpaces(char[] a, int n) {
int i = 0, j = 0;
while (j < n) {
while (j < n && a[j] == ' ') j++; // skip spaces
while (j < n && a[j] != ' ') a[i++] = a[j++]; // keep non spaces
while (j < n && a[j] == ' ') j++; // skip spaces
if (j < n) a[i++] = ' '; // keep only one space
}
return new String(a).substring(0, i);
}
// reverse a[] from a[i] to a[j]
private void reverse(char[] a, int i, int j) {
while (i < j) {
char t = a[i];
a[i++] = a[j];
a[j--] = t;
}
}
}
*/