Reverse Integer

[fkdl0048]

class Solution {
public:
    int reverse(int x) {
        int ans = 0;
        while (x != 0){
            int digit = x % 10;
            
            if ((ans > INT_MAX / 10) || (ans < INT_MIN / 10))
                return 0;

            ans = ans * 10 + digit;
            x = x / 10;
        }

        return ans;
    }
};