-
Notifications
You must be signed in to change notification settings - Fork 25
/
Copy path113_PathSumII.py
60 lines (48 loc) · 1.4 KB
/
113_PathSumII.py
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
# coding: utf8
"""
题目链接: https://leetcode.com/problems/path-sum-ii/description.
题目描述:
Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given sum.
For example:
Given the below binary tree and sum = 22,
5
/ \
4 8
/ / \
11 13 4
/ \ / \
7 2 5 1
return
[
[5,4,11,2],
[5,8,4,5]
]
"""
# Definition for a binary tree node.
class TreeNode(object):
def __init__(self, x):
self.val = x
self.left = None
self.right = None
class Solution(object):
def pathSum(self, root, sum):
"""
:type root: TreeNode
:type sum: int
:rtype: List[List[int]]
"""
if not root:
return []
ans = []
sub = []
self.recursive_path_sum(root, sum, sub, ans)
return ans
def recursive_path_sum(self, root, sum, sub, ans):
sub.append(root.val)
if not root.left and not root.right and sum == root.val:
ans.append(sub[:])
if root.left:
self.recursive_path_sum(root.left, sum - root.val, sub, ans)
if root.right:
self.recursive_path_sum(root.right, sum - root.val, sub, ans)
sub.pop()