-
Notifications
You must be signed in to change notification settings - Fork 25
/
Copy path110_BalancedBinaryTree.py
65 lines (46 loc) · 1.37 KB
/
110_BalancedBinaryTree.py
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
# coding: utf8
"""
题目链接: https://leetcode.com/problems/balanced-binary-tree/description.
题目描述:
Given a binary tree, determine if it is height-balanced.
For this problem, a height-balanced binary tree is defined as:
a binary tree in which the depth of the two subtrees of every node never differ by more than 1.
Example 1:
Given the following tree [3,9,20,null,null,15,7]:
3
/ \
9 20
/ \
15 7
Return true.
Example 2:
Given the following tree [1,2,2,3,3,null,null,4,4]:
1
/ \
2 2
/ \
3 3
/ \
4 4
Return false.
"""
# Definition for a binary tree node.
class TreeNode(object):
def __init__(self, x):
self.val = x
self.left = None
self.right = None
class Solution(object):
def isBalanced(self, root):
"""
:type root: TreeNode
:rtype: bool
"""
if not root:
return True
return self.isBalanced(root.left) and self.isBalanced(root.right) and abs(
self.recursive_tree_of_depth(root.left) - self.recursive_tree_of_depth(root.right)) <= 1
def recursive_tree_of_depth(self, root):
if not root:
return 0
return max(self.recursive_tree_of_depth(root.left), self.recursive_tree_of_depth(root.right)) + 1