- See Code
Complexity T : O(N) M : O(n)
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
def minDiffInBST(self, root: TreeNode) -> int:
stack = []
ans, pre = float("inf"), float("-inf")
while root or stack:
if root:
stack.append(root)
root = root.left
else:
root = stack.pop()
ans = min(ans, root.val - pre)
pre = root.val
root = root.right
return ans