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is:issue is:open 报错暂不支持xxx漏洞利用解决方案 #19

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qq87234770 opened this issue Dec 30, 2020 · 2 comments

qq87234770 commented Dec 30, 2020

改1502行
if name not in s2_list:
为
if name not in s2_dict:
即可

admln commented Jul 5, 2022

楼上正解

yanxiao588 commented Nov 27, 2024

终于解决了，感谢大佬

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