refactor: convert string with anomalous backslash into a raw string (#29

)

Backslash is present in the literal string but is not a valid escape sequence. If it is intended to be an escape sequence, use the correct escape characters. If it is intended to be a literal backslash, it can either be replaced with with an escaped backslash `\\`, or you can add an `r` prefix to make it a "raw" string.

Co-authored-by: deepsource-autofix[bot] <62050782+deepsource-autofix[bot]@users.noreply.github.com>

src/plugins/ncm/__init__.py

@@ -85,10 +85,10 @@ async def music_reply_rule(event: Union[GroupMessageEvent, PrivateMessageEvent])
                      rule=Rule(music_set_rule),
                      block=False)
 '''功能设置'''
-music_regex = on_regex("(song|url)\?id=([0-9]+)(|&)",
+music_regex = on_regex(r"(song|url)\?id=([0-9]+)(|&)",
                        block=False)
 '''歌曲id识别'''
-playlist_regex = on_regex("playlist\?id=([0-9]+)&",
+playlist_regex = on_regex(r"playlist\?id=([0-9]+)&",
                           block=False)
 '''歌单识别'''
 music_reply = on_message(

src/plugins/ncm/data_source.py

@@ -312,7 +312,7 @@ async def download(self, ids: list, check=False, lid=0, is_zip=False):  # 下载
             url = data[i]["url"]
             nid = data[i]["id"]
             filename = f"{name[i]}.{data[i]['type']}"
-            filename = re.sub('[\/:*?"<>|]', "-", filename)
+            filename = re.sub(r'[\/:*?"<>|]', "-", filename)
             file = Path.cwd().joinpath("music").joinpath(filename)
             config = {
                 "id": int(nid),